2w^2+2w-1300=0

Solution for 2w^2+2w-1300=0 equation:

2w^2+2w-1300=0

a = 2; b = 2; c = -1300;
Δ = b2-4ac
Δ = 22-4·2·(-1300)
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-102}{2*2}=\frac{-104}{4}
=-26
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+102}{2*2}=\frac{100}{4}
=25
$